annotate OrthancServer/Resources/DicomConformanceStatement.py @ 4832:2e71a08eea15 openssl-3.x

integration mainline->openssl-3.x
author Sebastien Jodogne <s.jodogne@gmail.com>
date Thu, 25 Nov 2021 19:02:38 +0100
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1 #!/usr/bin/python
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2
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3 # Orthanc - A Lightweight, RESTful DICOM Store
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4 # Copyright (C) 2012-2016 Sebastien Jodogne, Medical Physics
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5 # Department, University Hospital of Liege, Belgium
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6 # Copyright (C) 2017-2021 Osimis S.A., Belgium
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7 # Copyright (C) 2021-2021 Sebastien Jodogne, ICTEAM UCLouvain, Belgium
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8 #
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9 # This program is free software: you can redistribute it and/or
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10 # modify it under the terms of the GNU General Public License as
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11 # published by the Free Software Foundation, either version 3 of the
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12 # License, or (at your option) any later version.
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13 #
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14 # This program is distributed in the hope that it will be useful, but
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15 # WITHOUT ANY WARRANTY; without even the implied warranty of
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16 # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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17 # General Public License for more details.
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18 #
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19 # You should have received a copy of the GNU General Public License
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20 # along with this program. If not, see <http://www.gnu.org/licenses/>.
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25 # This file injects the UID information into the DICOM conformance
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26 # statement of Orthanc
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28 import re
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30 # Read the conformance statement of Orthanc
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31 with open('DicomConformanceStatement.txt', 'r') as f:
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32 statements = f.readlines()
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33
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34 # Create an index of all the DICOM UIDs that are known to DCMTK
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35 uids = {}
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36 with open('/usr/include/dcmtk/dcmdata/dcuid.h', 'r') as dcmtk:
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37 for l in dcmtk.readlines():
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38 m = re.match(r'#define UID_(.+?)\s*"(.+?)"', l)
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39 if m != None:
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40 uids[m.group(1)] = m.group(2)
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41
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42 # Loop over the lines of the statement, looking for the "|" separator
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43 with open('/tmp/DicomConformanceStatement.txt', 'w') as f:
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44 for l in statements:
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45 m = re.match(r'(\s*)(.*?)(\s*)\|.*$', l)
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46 if m != None:
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47 name = m.group(2)
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48 uid = uids[name]
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49 f.write('%s%s%s| %s\n' % (m.group(1), name, m.group(3), uid))
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50
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51 else:
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52 # No "|" in this line, just output it
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53 f.write(l)